-p^2+44-7p=0

Solution for -p^2+44-7p=0 equation:

-p^2+44-7p=0

We add all the numbers together, and all the variables

-1p^2-7p+44=0

a = -1; b = -7; c = +44;
Δ = b2-4ac
Δ = -72-4·(-1)·44
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-15}{2*-1}=\frac{-8}{-2}
=+4
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+15}{2*-1}=\frac{22}{-2}
=-11
$